Dear Reader ,

In my experience , the subject of estimation is quite boring to the students as well as field people.

In that context , we are going through a series of articles **devoted to the arithmetic involved in construction.**

We have already discussed the **estimation of materials in concrete**

( Read post : Vow..what a concrete )

Now we shall travel in the masonry today.

**Just keep your patience when you read.**

**If you get bored , just Stop and take a break.**

Take a scrap pad and a calculator and do some jugglery yourselves.

**That’s how you shall keep aligned .**

**Re-continue and reflect as many times as you feel.**

There is no hurry.

**Happy Calculating !**

**Overview:**

( Read : Throw the stone..carefully )

We shall be able to find out the :

**Number of bricks needed for the masonry work and also the mortar needed for the job.**

**In other words ,for a given masonry wall we shall be able to compute:**

**1.**

**No**

**of**

**bricks**

**2.****No**** ****of**** ****cement**** bags**

**3.****Sand**

**total**

**material**

**cost**

**.**

**This**** ****shall**** ****help**** ****us**** ****in****:**

**1.****Budgeting**** ****for**** ****materials**

**2.****Ordering**** ****the**** ****material**

**The**** D****ata****:**

The brick wall which we need to **build is 5 m long, 4 m high and it is 200 mm thick.**

It is to be jointed in **Cement mortar 1:6.**

The bricks of size **200 mm x100 mm x 70 mm **have been **approved****.**

**The method:**

1.Calculate the volume of one brick :

**0.2m x 0.10m x 0.07m =** **0.0014** CuM.

2.Find number of bricks per CuM:

**= 1/0.0014 = 714 ****nos****.**

**714**bricks shall be needed if

**there is no mortar joint. Right ?**

3. Now,assume that there is a **mortar** **joint of 10 mm thickness between the bricks.**

So, increase each dimension of brick by 10 mm.

Thus,the volume of each brick with mortar shall be :

**0.21 x 0.110 x 0.08** =**0.001848 CuM.**

**Again, Find number of bricks per CuM:**

**= 1/0.0011848 = 541 nos.**

5.**Thus, number of bricks have reduced from 714 to 541 due to the presence of mortar.**

6.Therefore, **714 – 541 = 173 ****Bricks**** **represent the volume of cement mortar.

**173**

**x**

**0.0014= 0.2422**

**CuM**

**.**

**7.**

**Summary**

**I**

**:**

We shall need **541** **bricks** and **0.24** **CuM** of **cement mortar for 1 CuM of brick work.**

**8.****Now**** ****we**** ****also**** ****need**** ****to**** ****find**** ****out**** ****how**** ****many**** ****cement**** ****bags**** ****and**** ****how**** ****much**** ****quantity**** ****of**** ****sand**** ****is**** ****needed**** **

**f****or**** 0.24 ****CuM**** ****of**** ****mortar**** .**

**1**

**CuM**

**.**

The mix is **CM**** 1:6.**

We shall use **dry mix method.**

**Cement**

**: [1.52/(1+6)]x 28.8 =**

**[0.2171]x 28.8**

**= 6.25**

**Bags**

**Sand****: [0.2171] x 6 = 1.302 ****CuM****.**

**Consumption of materials for 1 CuM of cement mortar (1:6):**

**Cement****: 6.25 ****Bags**

**Sand****: 1.302 ****CuM****.**

**we actually need only 0.24 CuM of mortar for 1 CuM of brick work**

Hence for 0.24 CuM of mortar , we shall need :

**Cement: 6.25 Bags x 0.24 =1.5 bags**

**Sand: 1.302 ****CuM. ****x**** 0.24= 0.3125 CuM.**

**9.Summary II:**

Consumption of materials for 1 CuM of Brickwork :

**Cement: 1.5 bags**

**Sand: **** 0.3125 CuM.**

**Bricks****: 541 ****Bricks**

10.Now we are at the final lap:

Volume of brick wall:

**5 x 4x 0.2 = 4 CuM**

**Cement: 1.5 bags**** ****x**** 4 = ****6 ****bags**

**Sand: **** 0.3125 CuM. ****x 4 = 1.25 ****CuM****.**

**Bricks****: 541 ****Bricks**** x 4 = 2164 Bricks**

**If**** ****the**** ****unit**** ****rates**** ****are**** ****known**** ****we**** ****can**** also ****find**** ****out**** ****total**** ****cost**** ****of**** ****the**** ****materials****.**

**Bricks : INR 4200 per 1000. [ INR 4.2 per no ]**

**Sand : INR 4500 per Brass or 100 Cft. **

**[ INR 45 per cft or 45 x 35.29 = INR 1588 per cuM.]**

**Cement : INR 300 per bag of 50 Kg.**

The material cost shall be as follows :

**Cement: **** ****6 ****bags@ 300 = 1800**

**Sand: **** ****1.25 ****CuM****.@ 1588 = 1985**

**Bricks****: ****2164 Bricks@ 4.2 = 9088**

Total cost :**1800 + 1985 + 9088 **

**= INR 12,873 **

**12.** **Now we can find out the materials cost per CuM of brick work :**

**12,873 /4 = INR 3218.25 per CuM of brick work **

or **3218.25/35.29 = INR 91.19 per Cubic feet of brick work**

Author’s note :

Dear Reader ,

Hope you have understood the basics.

1.Remember , you don’t have to do all this calculation every .

Just memorize the unit cost i.e **INR 3218.25 per CuM or INR 91.19 per Cubic feet of brick work .**

**As long as the material rates are the same, the cost shall be the same.**

**2. For those comfortable with spread sheets , once do this calculation in the spread sheet with proper formulae. Later , when any of the variable changes ,****the moment you revise that figure, the entire computations shall be automatically revised.**

Its really a fun.

believe me.

**Happy journey on the path of estimations.**

900×450×450 mm brick chamber brick calculate

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Yogesh

Great to see this.

There is already an article about edge column footing.

Have u gone through ?

Pros and Cons ..let me post another article soon.

Thanks for the fantastic suggestion.

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