Dear Friends ,

We determined the weight of the Re-Bars for a one way slab in earlier post.

Refer the post here : **ONE WAY SLAB : REBARS **

Today , let us find out the cost of materials in totality.

Please remember this is only the cost of materials.

For finding out the complete cost of this item , we shall need to add many other elements.

That we shall learn in a separate post.

Stay connected.

Bye

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So nice of you to share this information. I am sure everyone would be eager for more of it. Very very helpful. The best part is you make complicated things look so simple and easy.

Thank you sir.

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Thank you so much Anshul for the appreciations.

I am glad that this is useful to the construction fraternity.

Stay connected.

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Hello sir i have been recently visiting your blog and this is very useful. i need your suggestions regarding concrete mi design . if i am using m 20 concrete then i know the ratio as 1: 1.5: 3 which says that around 5.2 bags of cement , 0.27 c.m of sand and 0.545 c.m of aggregate but on site i tried using this ratio for eample: the vessels which we used to make this m20 concrete . it takes 4 nos of this vessel to occupy 1 bag of cement of 50 kg so i calculated the sand and metal quantiy as 4*1.5= 6 veseels of sand and similarly 4*3=12 parts of metal but this results into un fit concrete misc which i can see visibly so can u help me what to do in this mateer as theoretical ratio of m20 doesnt produce good concrete

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Hello ,

Great to know about your experiments at site.

Shall explain this to blog within 3 days.

In case I forget, do remind me .

Stay connected

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How u calculate the 28.8 of cement bag…i can’t get it

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how u calculated 28.8 for quantity of cement bag On 13 Jun 2016 9:14 pm, “Construction basics re-told” wrote:

> Santosh Kulkarni posted: “Dear Friends , We determined the weight of the > Re-Bars for a one way slab in earlier post. Refer the post here : ONE WAY > SLAB : REBARS Today , let us find out the cost of materials in totality. > Please remember this is only the cost ” >

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Alright .

Let me explain.

The bulk density of cement is 1440 Kg /cum.

In a bag , we have 50 kg.

Therefore , in 1 cum , we shall have 1440 kg / 50 = 28.8 bags of cement.

Got it ?

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